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What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
multiset
s1.insert(v.begin(),v.end());
pair
range = s1.equal_range(6);
while (range.first != range.second) {
cout<<*range.first<<" "; range.first++;
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out< } }; struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return start++ ; }}; int main() { vector generate(v1.rbegin(), v1.rend(), Sequence(1)); rotate(v1.begin(),v1.begin() + 1, v1.end() ); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int() const { return val; };};
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; fstream f("test.out", ios::trunc|ios::out); list l(t, t+10); for_each(l.begin(), l.end(), Out(f)); f.close(); f.open("test.out"); for( ; f.good() ; ) { B i; f>>i; cout< } f.close(); return 0; }
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: one two three
#include
#include
using namespace std;
int main ()
{
string a;
cin>>a;
What will happen when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
int main() {
int t[] = { 3, 4, 2, 1, 0, 3, 4, 1, 2, 0 };
vector
multimap
for (vector
stringstream s;s << *i << *i;
m.insert(pair
}
pair
range = m.equal_range(2);
for (multimap
cout << i?>first << " ";
}
return 0;
}
The output will be:
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