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What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int myints[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
set
set
for(set
cout<<*i<<" ";
}
for(set
cout<<*i<<" ";
}
cout< return 0; }
What will happen when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
set
s1.insert(v.begin(),v.end());
pair
range = s1.equal_range(6);
cout<<*range.first<<" "<<*range.second< return 0; } The output will be:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
void print(int v) { cout< struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return 10*(1+(start++ %3)); } }; int main() { vector generate_n(v1.begin(), 10, Sequence(1)); remove(v1.begin(), v1.end(), 10); for_each(v1.begin(), v1.end(), print);cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< struct Add { int operator()(int & a, int & b) { return a+b; } }; int main() { int t[]={1,2,3,4,5,6,7,8,9,10}; vector vector transform(v1.begin(), v1.end(), v2.begin(), bind1st(1,Add())); for_each(v2.rbegin(), v2.rend(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
template
class A {
T_v;
public:
A() {}
A(T v): _v(v){}
T getV() { return _v; }
void add(T & a);
void add(string & a);
};
template
void A
void A
_v.insert(0, a);
}
int main()
{
A
string s(" world!");
a.add(s);
cout << a.getV() < return 0; }
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